How to get current page in pages Symfony 5 without duplicate code?

I want get the current page and give an active class without duplicate code in symfony 5.
Here is the code example :

    <li class="{{ app.request.get('_route_')=='home' ? 'active':''}}">
       <a href="{{path('home')}}">Home</a> 
    <li class="{{ app.request.get('_route_')=='contact' ? 'active':''}}">
        <a href="{{path('contact')}}">Contact</a> 


Source: Symfony Questions

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